Soluzione del esercizio 159 di Matematica.blu: Algebra, Geometria, Statistica, Vol. 1

$(8-2\cdot2+1)^3:(8+2-5)^2+(8+2\cdot2)^2:(8-2)$ $=$ $(8-4+1)^3:5^2+(8+4)^2:6$ $=$ $5^3:5^2+12^2:6$ $=$ $5^{3-2}+144:6$ $=$ $5+24$ $=$ $29$