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Soluzione del esercizio 152 di Matematica.blu: Algebra, Geometria, Statistica, Vol. 1
Esercizi svolti per il libro Matematica.blu: Algebra, Geometria, Statistica, Vol. 1
Capitolo
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Capitolo 1: I numeri naturali e i numeri interi
Esercizio
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100 (video)
101 (video)
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108 (video)
109 (video)
110 (video)
111 (video)
112 (video)
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114 (video)
115 (video)
116 (video)
117 (video)
118 (video)
119 (video)
120 (video)
121 (video)
122 (video)
123 (video)
124 (video)
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Soluzione
(
7
−
3
)
3
−
3
⋅
7
⋅
3
(7-3)^3-3 \cdot 7 \cdot 3
(
7
−
3
)
3
−
3
⋅
7
⋅
3
=
=
=
4
3
−
3
⋅
21
4^3-3\cdot21
4
3
−
3
⋅
21
=
=
=
64
−
63
64-63
64
−
63
=
=
=
1
1
1
2
⋅
2
⋅
3
2
−
(
2
+
3
)
2
2\cdot 2 \cdot 3^2 - (2+3)^2
2
⋅
2
⋅
3
2
−
(
2
+
3
)
2
=
=
=
2
⋅
2
⋅
9
−
5
2
2\cdot 2 \cdot 9 - 5^2
2
⋅
2
⋅
9
−
5
2
=
=
=
36
−
25
36-25
36
−
25
=
=
=
11
11
11
2
⋅
9
2
+
1
2
−
2
(
9
−
1
)
2
2 \cdot 9^2 + 1^2 - 2(9-1)^2
2
⋅
9
2
+
1
2
−
2
(
9
−
1
)
2
=
=
=
2
⋅
81
+
1
−
2
⋅
8
2
2 \cdot 81 + 1 - 2 \cdot 8^2
2
⋅
81
+
1
−
2
⋅
8
2
=
=
=
162
+
1
−
2
⋅
64
162+1-2\cdot64
162
+
1
−
2
⋅
64
=
=
=
162
+
1
−
128
162+1-128
162
+
1
−
128
=
=
=
163
−
128
163-128
163
−
128
=
=
=
35
35
35