Esercizi svolti per il libro Matematica.blu: Algebra, Geometria, Statistica, Vol. 1
Soluzione
{[(1+2⋅25−11):8+8]−1}:4+3⋅2+9⋅2\{[(1+2\cdot25-11):8+8]-1\}:4+3\cdot2+9\cdot2{[(1+2⋅25−11):8+8]−1}:4+3⋅2+9⋅2 === {[(1+50−11):8+8]−1}:4+6+18\{[(1+50-11):8+8]-1\}:4+6+18{[(1+50−11):8+8]−1}:4+6+18 === {[40:8+8]−1}:4+6+18\{[40:8+8]-1\}:4+6+18{[40:8+8]−1}:4+6+18 === {[5+8]−1}:4+6+18\{[5+8]-1\}:4+6+18{[5+8]−1}:4+6+18 === {13−1}:4+6+18\{13-1\}:4+6+18{13−1}:4+6+18 === 12:4+6+1812:4+6+1812:4+6+18 === 3+6+18=273+6+18=273+6+18=27