Esercizi svolti per il libro Matematica.blu: Algebra, Geometria, Statistica, Vol. 1
Soluzione
{[(9+11):4]2:5−1}⋅8−[49:(6+1)+8+1]\{[(9+11):4]^2:5-1\}\cdot8-[49:(6+1)+8+1]{[(9+11):4]2:5−1}⋅8−[49:(6+1)+8+1] === {[20:4]2:5−1}⋅8−[49:7+8+1]\{[20:4]^2:5-1\}\cdot8-[49:7+8+1]{[20:4]2:5−1}⋅8−[49:7+8+1] === {52:5−1}⋅8−[7+8+1]\{5^2:5-1\}\cdot8-[7+8+1]{52:5−1}⋅8−[7+8+1] === {52−1−1}⋅8−16\{5^{2-1}-1\}\cdot8-16{52−1−1}⋅8−16 === {5−1}⋅8−16\{5-1\}\cdot8-16{5−1}⋅8−16 === 4⋅8−16=32−16=164\cdot8-16=32-16=164⋅8−16=32−16=16