Esercizi svolti per il libro Matematica.blu: Algebra, Geometria, Statistica, Vol. 1
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Soluzione
{[2⋅(10)−15]⋅[3+4⋅(3)−14]+2}:7\{[2\cdot(10)-15]\cdot[3+4\cdot(3)-14]+2\}:7{[2⋅(10)−15]⋅[3+4⋅(3)−14]+2}:7 === {[(20)−15]⋅[3+(12)−14]+2}:7\{[(20)-15]\cdot[3+(12)-14]+2\}:7{[(20)−15]⋅[3+(12)−14]+2}:7 === {[5]⋅[1]+2}:7\{[5]\cdot[1]+2\}:7{[5]⋅[1]+2}:7 === {[5]+2}:7\{[5]+2\}:7{[5]+2}:7 === {7}:7=1\{7\}:7=1{7}:7=1