Esercizi svolti per il libro Matematica.blu: Algebra, Geometria, Statistica, Vol. 1 con autore Massimo Bergamini, Anna Trifone, Graziella Barozzi
Domanda
33−{3⋅23−[(5⋅22−7)2:13+12:(3⋅23−22⋅3)]:2}2:1723^3-\{3\cdot2^3-[(5\cdot2^2-7)^2:13+12:(3\cdot2^3-2^2\cdot3)]:2\}^2:17^233−{3⋅23−[(5⋅22−7)2:13+12:(3⋅23−22⋅3)]:2}2:172
Soluzione
27−{3⋅8−[(5⋅4−7)2:13+12:(3⋅8−4⋅3)]:2}2:28927-\{3\cdot8-[(5\cdot4-7)^2:13+12:(3\cdot8-4\cdot3)]:2\}^2:28927−{3⋅8−[(5⋅4−7)2:13+12:(3⋅8−4⋅3)]:2}2:289 === 27−{24−[(20−7)2:13+12:(24−12)]:2}2:28927-\{24-[(20-7)^2:13+12:(24-12)]:2\}^2:28927−{24−[(20−7)2:13+12:(24−12)]:2}2:289 === 27−{24−[132:13+12:12]:2}2:28927-\{24-[13^2:13+12:12]:2\}^2:28927−{24−[132:13+12:12]:2}2:289 === 27−{24−[13+1]:2}2:28927-\{24-[13+1]:2\}^2:28927−{24−[13+1]:2}2:289 === 27−{24−14:2}2:28927-\{24-14:2\}^2:28927−{24−14:2}2:289 === 27−{24−7}2:28927-\{24-7\}^2:28927−{24−7}2:289 === 27−172:28927-17^2:28927−172:289 === 27−289:28927-289:28927−289:289 === 27−1=2627-1=2627−1=26
