Unità 6 - Polinomi

Determina la somma e la differenza dei polinomi delle seguenti coppie.

$\dfrac{1}{2}x-2y$ , $\dfrac{3}{2}x+2y$

$(\dfrac{1}{2}x-2y)+(\dfrac{3}{2}x+2y)$ $=$ $\dfrac{1}{2}x-2y+\dfrac{3}{2}x+2y$ $=$ $(\dfrac{1}{2}x+\dfrac{3}{2}x)+(2y-2y)$ $=$ $\dfrac{\cancel4}{\cancel2}x$ $=$ $2x$
$(\dfrac{1}{2}x-2y)-(\dfrac{3}{2}x+2y)$ $=$ $\dfrac{1}{2}x-2y-\dfrac{3}{2}x-2y$ $=$ $(\dfrac{1}{2}x-\dfrac{3}{2}x)$ $+$ $(-2y-2y)$ $=$ $-\dfrac{2}{2}x+(-4y)$ $=$ $-x-4y$